最小的K个数

给定一个无序数组,找到其中最小的K个数

利用最大堆,只要维护堆内有k个数即可

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//利用最大堆
public static int[] getMinKNumByHeap(int[]arr ,int k){
if(arr==null ||arr.length<k|| k<0){
return null;
}
int[] kHeap = new int[k];
for(int i =0 ; i<k; i++){
heapInsert(kHeap,arr[i],i);
}
for(int i=k; i<arr.length; i++){
if(kHeap[0]>arr[i]){
kHeap[0] = arr[i];
heapify(kHeap, 0, k);
}
}
return kHeap;
}
//建堆的过程
public static void heapInsert(int[] heap, int value, int index){
heap[index] = value;
int parent = (index-1)/2;
while(index!=0){
if(heap[index]>heap[parent]){
swap(heap,index,parent);
index = parent;
}else{
break;
}
}
}
//调整的过程
public static void heapify(int[] heap, int index, int heapSize){
int left = 2*index +1;
int right = 2*index +2;
int largest = index;
while(left < heapSize){
if(heap[index]<heap[left]){
//swap(heap,index,left);
largest = left;
}
if(right < heapSize && heap[largest]<heap[right]){
largest = right;
}
if(index!=largest){
swap(heap,index,largest);
}else{
break;
}
index = largest;
left = 2*index +1;
right = 2*index +2;
}

}
public static void swap(int[] arr, int low, int high){
int temp = arr[low];
arr[low] = arr[high];
arr[high] = temp;
}

快排思想, 无需全部排序,保证前k个数有序即可

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public static int partition(int[] arr,int start,int end){
if(arr==null || arr.length==0){
return -1;
}
int l = start;
int r = end;
int temp = arr[l];
if(l<r){
while(l<r && temp >= arr[r]){
r--;
}
if(l<r){
arr[l++]=arr[r];
}
while(l<r && temp < arr[l]){
l++;
}
if(l<r){
arr[r--] = arr[l];
}
}
arr[l] = temp;
return l;
}
//利用快排思想
public static void getKNum(int[] arr,int start,int end, int k){
int index = partition(arr, start, end);
while(index != k-1){
if(index < k-1){
index = partition(arr, index+1, end);
}else if(index > k-1){
index = partition(arr, start, index-1);
}else{
return;
}
}
}